AMC 12A 2023 (Problem 19)

What is the product of all the solutions to the equation log7x2023log289x2023=log2023x2023?\log_{7x}2023\cdot\log_{289x}2023=\log_{2023x}2023?
(A)  (log20237log2023289)2\text{(A)}\;(\log_{2023}7\cdot\log_{2023}289)^2(B)  log20237log2023289\text{(B)}\;\log_{2023}7\cdot\log_{2023}289(C)  1\text{(C)}\;1(D)  log72023log2892023\text{(D)}\;\log_72023\cdot\log_{289}2023(E)  (log72023log2892023)2\text{(E)}\;(\log_72023\cdot\log_{289}2023)^2