AMC 8 2022 (Problem 8)What is the value of 13⋅24⋅35⋯1820⋅1921⋅2022\dfrac{1}{3}\cdot\dfrac{2}{4}\cdot\dfrac{3}{5}\cdots\dfrac{18}{20}\cdot\dfrac{19}{21}\cdot\dfrac{20}{22}31⋅42⋅53⋯2018⋅2119⋅2220?(A) 1462\text{(A)}\;\frac{1}{462}(A)4621(B) 1231\text{(B)}\;\frac{1}{231}(B)2311(C) 1132\text{(C)}\;\frac{1}{132}(C)1321(D) 2213\text{(D)}\;\frac{2}{213}(D)2132(E) 122\text{(E)}\;\frac{1}{22}(E)221Related TopicsCoreToolkit 5 — Telescoping seriesHints (2)Hint 1Hint 2Final Answer(B) 1231\frac{1}{231}2311Related Problems (4)AMC 10B 2022 (Problem 9)AMC 12B 2025 (Problem 7)MATHCOUNTS 2026 State Sprint Round (Problem 24)AIME II 2025 (Problem 4)