Math Gold Medalist
Lor
2018 AMC 8
Problem 24
In the cube with opposite vertices and and are the midpoints of edges and respectively. Let be the ratio of the area of the cross-section to the area of one of the faces of the cube. What is
Pythagorean TheoremArea
Area of EJCI = (EC.JI)/2
EC=a.sqrt(3)
JI=a.sqrt(2)
2020 AMC 8 Problem 18
Solution